(x^2+10x+25)+(x^2-4x+4)=9

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Solution for (x^2+10x+25)+(x^2-4x+4)=9 equation: 



(x^2+10x+25)+(x^2-4x+4)=9

We move all terms to the left:

(x^2+10x+25)+(x^2-4x+4)-(9)=0

We get rid of parentheses

x^2+x^2+10x-4x+25+4-9=0

We add all the numbers together, and all the variables

2x^2+6x+20=0

a = 2; b = 6; c = +20;
Δ = b2-4ac
Δ = 62-4·2·20
Δ = -124
Delta is less than zero, so there is no solution for the equation

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